LeetCode 198. House Robber(Python)

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题目描述:
You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will automatically contact the police if two adjacent houses were broken into on the same night.

Given a list of non-negative integers representing the amount of money of each house, determine the maximum amount of money you can rob tonight without alerting the police.

思路:
这是一道标准的动态规划问题,创建一个list保存小偷到每个房间能拿到最多的钱,第一个房间为本身,第二个为前两个房间较大者。第i个房间便为(状态转移方程):

dp[i] = max(dp[i - 1], dp[i - 2] + nums[i])

AC代码:

class Solution(object):    def rob(self, nums):        """        :type nums: List[int]        :rtype: int        """        dp = [0] * len(nums)        if not nums:            return 0        elif len(nums) == 1:            return nums[0]        dp[0] = nums[0]        dp[1] = max(nums[0], nums[1])        for i in range(2, len(nums)):            dp[i] = max(nums[i] + dp[i - 2], dp[i - 1])        return dp[-1]