七夕到了, 很漂亮的生成3D红玫瑰花的小小程序的源码,七夕特别制作

来源:互联网 发布:简述什么是大数据时代 编辑:程序博客网 时间:2024/03/29 15:00

先上图:



代码如下:


<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"

"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-type" content="text/html;charset=utf-8">
<title>3D玫瑰花,七夕特别制作</title>
<meta name="Generator" content="EditPlus">
<meta name="Author" content="">
<meta name="Keywords" content="">
<meta name="Description" content="">
</head>
<body>
七夕情人节快乐!
<div id="demo" style="width: 520; height: 500px;">
<canvas id="c" height="500" width="500"></canvas>
</div>
<script>
var b = document.body;
var c = document.getElementsByTagName('canvas')[0];
var a = c.getContext('2d');
var canvas = document.getElementsByTagName('canvas')[0];
var ctx = canvas.getContext('2d');
document.body.clientWidth;
with (m = Math)
C = cos, S = sin, P = pow, R = random;
c.width = c.height = f = 500;
h = -250;
function p(a, b, c) {
if (c > 60)
return [
S(a * 7) * (13 + 5 / (.2 + P(b * 4, 4))) - S(b) * 50,
b * f + 50,
625 + C(a * 7) * (13 + 5 / (.2 + P(b * 4, 4))) + b
* 400, a * 1 - b / 2, a ];
A = a * 2 - 1;
B = b * 2 - 1;
if (A * A + B * B < 1) {
if (c > 37) {
n = (j = c & 1) ? 6 : 4;
o = .5 / (a + .01) + C(b * 125) * 3 - a * 300;
w = b * h;
return [
o * C(n) + w * S(n) + j * 610 - 390,
o * S(n) - w * C(n) + 550 - j * 350,
1180 + C(B + A) * 99 - j * 300,
.4
- a
* .1
+ P(1 - B * B, -h * 6)
* .15
- a
* b
* .4
+ C(a + b)
/ 5
+ P(
C((o * (a + 1) + (B > 0 ? w : -w)) / 25),
30) * .1 * (1 - B * B),
o / 1e3 + .7 - o * w * 3e-6 ]
}
if (c > 32) {
c = c * 1.16 - .15;
o = a * 45 - 20;
w = b * b * h;
z = o * S(c) + w * C(c) + 620;
return [ o * C(c) - w * S(c),
28 + C(B * .5) * 99 - b * b * b * 60 - z / 2 - h,
z,
(b * b * .3 + P((1 - (A * A)), 7) * .15 + .3) * b,
b * .7 ]
}
o = A * (2 - b) * (80 - c * 2);
w = 99 - C(A) * 120 - C(b) * (-h - c * 4.9) + C(P(1 - b, 7))
* 50 + c * 2;
z = o * S(c) + w * C(c) + 700;
return [ o * C(c) - w * S(c),
B * 99 - C(P(b, 7)) * 50 - c / 3 - z / 1.35 + 450, z,
(1 - b / 1.2) * .9 + a * .1, P((1 - b), 20) / 4 + .05 ]
}
}
var draw = setInterval(
'for(i=0;i<1e4;i++)if(s=p(R(),R(),i%46/.74)){z=s[2];x=~~(s[0]*f/z-h);y=~~(s[1]*f/z-h);if(!m[q=y*f+x]|m[q]>z)m[q]=z,a.fillStyle="rgb("+~(s[3]*h)+","+~(s[4]*h)+","+~(s[3]*s[3]*-80)+")",a.fillRect(x,y,1,1)}',
0);
var demo = document.getElementById('demo');
function redraw() {
draw = setInterval(
'for(i=0;i<1e4;i++)if(s=p(R(),R(),i%46/.74)){z=s[2];x=~~(s[0]*f/z-h);y=~~(s[1]*f/z-h);if(!m[q=y*f+x]|m[q]>z)m[q]=z,a.fillStyle="rgb("+~(s[3]*h)+","+~(s[4]*h)+","+~(s[3]*s[3]*-80)+")",a.fillRect(x,y,1,1)}',
0);
}
function clear_canvas() {
ctx.clearRect(0, 0, 520, 500);
}
function stop_draw(obj) {
clearInterval(obj);
}
</script>
</body>
</html>
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