poj1273Drainage Ditches

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最大流
#include<iostream>
using namespace std;
int n,m;
int c[205][205],f[205][205],s,t;
int pre[205],ans;
int find()
{
        int i=0,j=0,v,u,used[205];
        for(i=1;i<=n;i++)
        {
                pre[i]=-1;
                used[i]=0;
        }
        int q[205],head=0,end=0;
        q[end++]=s;
  used[s]=1;
        while(head<end)
        {
                u=q[head++];
                for(v=1;v<=n;v++)
                {
                        if(!used[v] && c[u][v]>f[u][v])
                        {
                                used[v]=1;
                                pre[v]=u;
                                q[end++]=v;
                                if(v==t)
                                        return 1;
                        }
                }
        }
        return 0;
}
void adjust()
{
        int Min=INT_MAX,v,u;
        v=t;
        while(v!=s)
        {
                u=pre[v];
                if(Min>(c[u][v]-f[u][v]))
                        Min=c[u][v]-f[u][v];
                v=u;
        }
        v=t;
        while(v!=s)
        {
                u=pre[v];
                f[u][v]+=Min;
                f[v][u]-=Min;
                v=u;
        }
        ans+=Min;
}
////
int main()
{
        int i,x,y,v;
        while(scanf("%d%d",&m,&n)==2)
        {
                memset(c,0,sizeof(c));
                memset(f,0,sizeof(f));
                for(i=0;i<m;i++)
                {
                        scanf("%d%d%d",&x,&y,&v);
                        c[x][y]+=v;
                }
                s=1,t=n;ans=0;
                while(find())
                        adjust();
                printf("%d/n",ans);
        }
        return 0;
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