设计一个基数排序的算法,将一组英文单词,按字典顺序排列。假设单词均由小写字母或空格构成,最长的单词有MaxLen个字母。
[参考解答]
#include <stdio.h>#include <malloc.h>#include <string.h>#define MaxLen 9 #define Radix 27 typedef char String[MaxLen+1]; typedef struct node{ String word; struct node *next;} LinkNode;void DispWord(String R[],int n) { int i; printf(" "); for (i=0; i<n; i++) printf("[%s] ",R[i]); printf("\n");}void PreProcess(String R[],int n){ int i,j; for (i=0; i<n; i++) { if (strlen(R[i])<MaxLen) { for (j=strlen(R[i]); j<MaxLen; j++) R[i][j]=' '; R[i][j]='\0'; } }}void EndProcess(String R[],int n){ int i,j; for (i=0; i<n; i++) { for (j=MaxLen-1; R[i][j]==' '; j--); R[i][j+1]='\0'; }}void Distribute(String R[],LinkNode *head[],LinkNode *tail[],int j,int n){ int i,k; LinkNode *p; for (i=0; i<n; i++) { if (R[i][j]==' ') k=0; else k=R[i][j]-'a'+1; p=(LinkNode *)malloc(sizeof(LinkNode)); strcpy(p->word,R[i]); p->next=NULL; if (head[k]==NULL) { head[k]=p; tail[k]=p; } else { tail[k]->next=p; tail[k]=p; } }}void Collect(String R[],LinkNode *head[]){ int k=0,i; LinkNode *p; for (i=0; i<Radix; i++) for (p=head[i]; p!=NULL; p=p->next) strcpy(R[k++],p->word);}void RadixSort(String R[],int n) { LinkNode *head[Radix],*tail[Radix]; int i,j; for (i=MaxLen-1; i>=0; i--) { for (j=0; j<Radix; j++) head[j]=tail[j]=NULL; Distribute(R,head,tail,i,n); Collect(R,head); }}int main(){ int n=6; String R[]= {"while","if","if else","do while","for","case"}; printf("排序前:\n"); DispWord(R,n); PreProcess(R,n); printf("预处理后:\n"); DispWord(R,n); RadixSort(R,n); printf("排序结果:\n"); DispWord(R,n); EndProcess(R,n); printf("最终结果:\n"); DispWord(R,n); printf("\n"); return 0;}