黑色星期五

在西方，星期五和数字13都代表着坏运气，两个不幸的个体最后结合成超级不幸的一天。所以，不管哪个月的十三日又恰逢星期五就叫“黑色星期五”。

输入：

    年份

输出：

    判断该年是否包含黑色星期五，如包含，给出具体日期

测试输入

2006

测试输出

There are 2 Black Fridays in year 2006.They are:2006/1/132006/10/13

代码

/*** @file source.cpp* @author 黄杨波* @date 2012-10-17* @description* 程序设计作业: 14. 黑色星期五*/#include<stdio.h>int yiyueyihao (int year);int runnian (int year);int blackFriday (int year);int blackMonth[12] = {};int main(){//freopen("simple.out","w",stdout);int day, month, year;int xingqi;int count;scanf("%d",&year);count = blackFriday (year);printf("%d\n",count);for(int n = 0; n < count; n++)printf("%d/13\n", blackMonth[n]);return 0;}int yiyueyihao (int year){int xingqi;int n, day = 1;for (n = 2; n <= year; n++){if (runnian (n - 1))day = day + 366;else day = day + 365;}xingqi = day % 7;return xingqi;} int runnian (int year){if (year % 400 == 0 || (year % 4 == 0 && year % 100 != 0))return 1;else return 0;}int blackFriday (int year){int month, day;int count = 0;day = yiyueyihao (year) + 12;for (month = 1; month <= 12; month++){if ((month - 1 == 1)||(month - 1 == 3)||(month - 1 == 5)||(month - 1 == 7)||(month - 1 == 8)||(month - 1 == 10))day = day + 31;else if (month - 1 == 2)day = day + 28 + runnian(year);else if ((month - 1 == 4)||(month - 1 == 6)||(month - 1 == 9)||(month - 1 == 11)) day = day + 30;if (day % 7 == 5){blackMonth[count] = month;count++;}}return count;}