[cpp] view plaincopyprint?
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- #include <iostream>
- #include <cstring>
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- using namespace std;
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- #define MAXLENGTH 8
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- void lcd_display (long size, long number)
- {
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- int digits[MAXLENGTH];
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- memset (digits, -1, sizeof (digits));
- if (number == 0)
- digits[MAXLENGTH - 1] = 0;
- else
- {
- for (int i = MAXLENGTH - 1; number > 0; i--)
- {
- digits[i] = number % 10;
- number /= 10;
- }
- }
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- string outline[5][10] = {
- " - ", " ", " - ", " - ", " ", " - ", " - ", " - ", " - ", " - ",
- "| |", " |", " |", " |", "| |", "| ", "| ", " |", "| |", "| |",
- " ", " ", " - ", " - ", " - ", " - ", " - ", " ", " - ", " - ",
- "| |", " |", "| ", " |", " |", " |", "| |", " |", "| |", " |",
- " - ", " ", " - ", " - ", " ", " - ", " - ", " ", " - ", " - "
- };
-
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- for (int row = 1; row <= (2 * size + 3); row++)
- {
- for (int i = 0; i < MAXLENGTH; i++)
- if (digits[i] != -1)
- {
- string line;
- if (row == 1)
- line = outline[0][digits[i]];
- if (2 <= row && row < (size + 2))
- line = outline[1][digits[i]];
- if (row == (size + 2))
- line = outline[2][digits[i]];
- if ((size + 3) <= row && row <= (2 * size + 2))
- line = outline[3][digits[i]];
- if (row == (2 * size + 3))
- line = outline[4][digits[i]];
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- cout << line[0];
- for (int j = 0; j < size; j++)
- cout << line[1];
- cout << line[2];
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- if (i < (MAXLENGTH - 1))
- cout << " ";
- }
- cout << '\n';
- }
- }
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- int main (int ac, char *av[])
- {
- long size, number;
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- while ((cin >> size >> number, size || number))
- {
- lcd_display (size, number);
- cout << endl;
- }
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- return 0;
- }
// LC-Display (液晶显示屏)// PC/UVa IDs: 110104/706, Popularity: A, Success rate: average Level: 1// Verdict: Accepted // Submission Date: 2011-04-09// UVa Run Time: 0.012s//// 版权所有(C)2011,邱秋。metaphysis # yeah dot net#include <iostream>#include <cstring>using namespace std;#define MAXLENGTH 8void lcd_display (long size, long number){// 将number拆分为单个的数字。int digits[MAXLENGTH];memset (digits, -1, sizeof (digits));if (number == 0)digits[MAXLENGTH - 1] = 0;else{for (int i = MAXLENGTH - 1; number > 0; i--){digits[i] = number % 10;number /= 10;}}// 定义每个数字的关键笔划。string outline[5][10] = { " - ", " ", " - ", " - ", " ", " - ", " - ", " - ", " - ", " - ","| |", " |", " |", " |", "| |", "| ", "| ", " |", "| |", "| |"," ", " ", " - ", " - ", " - ", " - ", " - ", " ", " - ", " - ","| |", " |", "| ", " |", " |", " |", "| |", " |", "| |", " |"," - ", " ", " - ", " - ", " ", " - ", " - ", " ", " - ", " - "};// 根据指定size将关键笔划扩大显示,实际上就是将关键笔划重复size次。for (int row = 1; row <= (2 * size + 3); row++){for (int i = 0; i < MAXLENGTH; i++)if (digits[i] != -1){string line;if (row == 1)line = outline[0][digits[i]];if (2 <= row && row < (size + 2))line = outline[1][digits[i]];if (row == (size + 2))line = outline[2][digits[i]];if ((size + 3) <= row && row <= (2 * size + 2))line = outline[3][digits[i]];if (row == (2 * size + 3))line = outline[4][digits[i]];// 输出关键笔划。cout << line[0];for (int j = 0; j < size; j++)cout << line[1];cout << line[2];// 在两个数字间要有一列空行。if (i < (MAXLENGTH - 1))cout << " ";}cout << '\n';}}int main (int ac, char *av[]){long size, number;while ((cin >> size >> number, size || number)){lcd_display (size, number);cout << endl;}return 0;}