Valid Palindrome
来源:互联网 发布:手机淘宝如何修改评价 编辑:程序博客网 时间:2024/04/26 05:59
Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.
For example,"A man, a plan, a canal: Panama"
is a palindrome."race a car"
is not a palindrome.
Note:
Have you consider that the string might be empty? This is a good question to ask during an interview.
For the purpose of this problem, we define empty string as valid palindrome.
代码:
class Solution {public:bool isPalindrome(string s){ int start=0,end=s.length()-1;while(start<end){while(start<end&&!isChar(s[start]))++start;while(start<end&&!isChar(s[end]))--end;if (start<end){if (!equal(s[start],s[end]))return false;++start;--end;}}return true;}bool isChar(char c){return (c>='0'&&c<='9')||(c>='a'&&c<='z')||(c>='A'&&c<='Z');}bool equal(char a,char b){if (a>='0'&&a<='9')return a==b;if (a>='A'&&a<='Z')a=a-'A'+'a';if (b>='A'&&b<='Z')b=b-'A'+'a';return a==b;}};
- Valid Palindrome
- Valid Palindrome
- Valid Palindrome
- Valid Palindrome
- Valid Palindrome
- Valid Palindrome
- valid palindrome
- Valid Palindrome
- Valid Palindrome
- Valid Palindrome
- Valid Palindrome
- Valid Palindrome
- Valid Palindrome
- Valid Palindrome
- Valid Palindrome
- Valid Palindrome
- Valid Palindrome
- Valid Palindrome
- 算法之约瑟夫环
- Android init
- 【越狱开发】调试iOS下没有加密的第三方程序
- class.forname()
- linux下的主要命令
- Valid Palindrome
- synchronized!!!!!!!!!!!!!!!!!!!!
- TinyXML使用
- win7 查看端口
- Android CTS 测试总结【转】
- 微软等面试100题系列--(61-80)
- SYBASE存储过程详解
- 求数组的子数组之和的最大值 .
- Mysql主从复制详解