Spring 注解版简单实例之强大的@Component(二)

来源：互联网发布：群体智能算法编辑：程序博客网时间：2024/04/20 13:30

1 接上一篇文章<Spring 注解版简单实例(一)>，此处为 @Component与@Resource相结合

在applicationContext.xml 文件中使用<context:component-scan>的效果，大大的减少了配置文件的书写,只添加一句

<context:component-scan base-package="com.bjsxt"/> 扫描包的路径

<?xml version="1.0" encoding="UTF-8"?><beans xmlns="http://www.springframework.org/schema/beans"       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"       xmlns:context="http://www.springframework.org/schema/context"       xsi:schemaLocation="http://www.springframework.org/schema/beans           http://www.springframework.org/schema/beans/spring-beans-2.5.xsd           http://www.springframework.org/schema/context           http://www.springframework.org/schema/context/spring-context-2.5.xsd"><context:annotation-config /><context:component-scan base-package="com.bjsxt"/></beans>

2 在UserServer和UserDAo类中分别更改为

UserSevice

package com.bjsxt.service;import javax.annotation.Resource;import org.springframework.beans.factory.annotation.Autowired;import org.springframework.beans.factory.annotation.Qualifier;import org.springframework.stereotype.Component;import com.bjsxt.dao.UserDAO;import com.bjsxt.model.User;@Component("userService")public class UserService {private UserDAO userDAO;  public void init() {System.out.println("init");}public void add(User user) {userDAO.save(user);}public UserDAO getUserDAO() {return userDAO;}@Resource(name="u")public void setUserDAO( UserDAO userDAO) {this.userDAO = userDAO;}}

userDAO

package com.bjsxt.dao.impl;import org.springframework.stereotype.Component;import com.bjsxt.dao.UserDAO;import com.bjsxt.model.User;@Component("u") public class UserDAOImpl implements UserDAO {public void save(User user) {//Hibernate//JDBC//XML//NetWorkSystem.out.println("user saved!");}}

3执行效果和以前的一样