uva 253 - Cube painting
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1,2,3,4,5,6六个面分别朝上 判断是否匹配 不匹配则顺时针旋转总共三次 每次都要判断是否匹配
总共24种状态 每种状态判断一遍 满足就输出TRUE 否则输出FALSE
哎 代码写得好搓
#include<cstdio>#include<cstring>int rot_up(char *p)//返回1说明完全匹配了{ char q[4]; q[0] = p[6];q[1] = p[7];q[2] = p[10];q[3] = p[11]; p[6] = q[1];p[7] = q[3];p[10] = q[0];p[11] = q[2]; for(int i = 0; i < 6;i++) if(p[i] != p[i+6])return 0; return 1;}int rot_right(char *p){ char q[4]; q[0] = p[7];q[1] = p[8];q[2] = p[9];q[3] = p[10]; p[7] = q[2];p[8] = q[0];p[9] = q[3];p[10] =q[1]; for(int i = 0; i < 6;i++) if(p[i] != p[i+6])return 0; return 1;}int main(){ #ifdef LOCAL freopen("in.txt","r",stdin); #endif // LOCAL char str[15]; while(gets(str)!=NULL) { int i,flag = 0; for(i = 0; i < 6;i++) if(str[i] != str[i+6])break; if(i == 6){printf("TRUE\n");continue;} char s[15]; strcpy(s,str); for(i = 0; i < 3&&flag!=1; i++) if(rot_right(s))flag = 1; if(flag == 1){printf("TRUE\n");continue;} for(i = 0; i < 4&&flag!=1; i++)//3面朝上 { if(i == 0)flag = rot_up(s); else flag = rot_right(s); } if(flag == 1){printf("TRUE\n");continue;} strcpy(s,str); for(i = 0; i < 4&&flag!=1; i++)//2面朝上 { if(i == 0)flag = rot_up(s); else flag = rot_right(s); } if(flag == 1){printf("TRUE\n");continue;} strcpy(s,str); //4面朝上 flag = rot_right(s); if(flag == 1){printf("TRUE\n");continue;} for(i = 0; i < 4&&flag!=1; i++) { if(i == 0)flag = rot_up(s); else flag = rot_right(s); } if(flag == 1){printf("TRUE\n");continue;} //5面朝上 strcpy(s,str); if(rot_right(s)){printf("TRUE\n");continue;} if(rot_right(s)){printf("TRUE\n");continue;} for(i = 0; i < 4&&flag!=1; i++) { if(i == 0)flag = rot_up(s); else flag = rot_right(s); } if(flag == 1){printf("TRUE\n");continue;} //6面朝上 strcpy(s,str); if(rot_up(s)){printf("TRUE\n");continue;} for(i = 0; i < 4&&flag!=1; i++) { if(i == 0)flag = rot_up(s); else flag = rot_right(s); } if(flag == 1){printf("TRUE\n");continue;} printf("FALSE\n"); } return 0;}
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- Uva 253 - Cube painting
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- UVA 253 Cube painting
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