spring mvc 之初级版

我也是最近刚开始接触spring mvc ,个人感觉比struts 方便多了。为了练手自己找了几个例子练手。

具体的操作步骤如下：

第一步：首先先导入MyEclipse 自带的spring 2.5 core和 spring 2.5 web 相关的 jar 包

第二步：配置applicationContext.xml  <?xml version="1.0" encoding="UTF-8"?><beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd">  <bean id="loginController" class="com.pb.controller.LoginController">   <property name="formView" value="login"></property>   <property name="successView" value="showAccount"></property>  </bean>   <bean id="editController" class="com.pb.controller.EditController">   <property name="successView" value="edit"></property>    </bean>  <bean id="urlMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">    <property name="mappings">     <props>        <prop key="/login.do">loginController</prop>        <prop key="/editBalance.do">editController</prop>     </props>    </property> </bean> <bean id="viewResolver"   class="org.springframework.web.servlet.view.InternalResourceViewResolver">      <property name="prefix" value="/" />      <property name="suffix" value=".jsp" /> </bean></beans>第三步：写一个Account实例第四步：编写处理业务逻辑的LoginController public class LoginController extends AbstractController {    private String formView; //跳转的属性名    private String successView;////跳转的属性名 @Override protected ModelAndView handleRequestInternal(HttpServletRequest request,   HttpServletResponse response) throws Exception {    //获取账号和密码  String cardNo=request.getParameter("cardNo");  String password=request.getParameter("password");  //进行业务逻辑处理  Account account=getAccount(cardNo, password);  Map<String, Object> map=new HashMap<String, Object>();  if(account!=null){   map.put("account", account);   //根据结果返回不同的ModelAnView   return new ModelAndView(successView, map);--前台要获取的值都封装在map里  }else{   map.put("error","卡号或密码不正确");   return new ModelAndView(formView,map);  }     } //获取账户和余额   public Account getAccount(String cardNo,String password ){    if(cardNo.equals("123")&& password.equals("123")){     Account account=new Account();     account.setCardNo(cardNo);     account.setBalance(90.9f);     return account;    }else{    return null;     }   } public String getFormView() {  return formView; } public void setFormView(String formView) {  this.formView = formView; } public String getSuccessView() {  return successView; } public void setSuccessView(String successView) {  this.successView = successView; }}第五步：页面配置要想后台接受页面的数据，要保持和后台接受的参数名要和页面上的传递的账户名和密码的name名一致 <form action="login.do" method="post">       <table>         <tr><td colspan="2">账户登录</td></tr>         <tr><td >帐户名：</td><td ><input type="text" name="cardNo" value=""/></td></tr>         <tr><td >密码：</td><td ><input type="password" name="password" value=""/></td></tr>         <tr><td colspan="2"><input type="submit"  value="提交"/><input type="reset"  value="重置"/></td></tr>       </table>    </form>