UVa 706 Problem: LC-Display (PC 110104)

/*A friend of yours has just bought a new computer. Before this, the most powerful machine he ever used was a pocket calculator. He is a little disappointed because he liked the LCD display of his calculator more than the screen on his new computer! To make him happy, write a program that prints numbers in LCD display style.InputThe input file contains several lines, one for each number to be displayed. Each line contains integers s and n, where n is the number to be displayed ( 0n99, 999, 999) and s is the size in which it shall be displayed ( 1s10). The input will be terminated by a line containing two zeros, which should not be processed.OutputPrint the numbers specified in the input file in an LCD display-style using s ``-'' signs for the horizontal segments and s ``|'' signs for the vertical ones. Each digit occupies exactly s + 2 columns and 2s + 3 rows. Be sure to fill all the white space occupied by the digits with blanks, including the last digit. There must be exactly one column of blanks between two digits.Output a blank line after each number. You will find an example of each digit in the sample output below.Sample Input2 123453 678900 0Sample Output      --   --        --    |    |    | |  | |      |    |    | |  | |         --   --   --   --    | |       |    |    |   | |       |    |    |      --   --        --  ---   ---   ---   ---   --- |         | |   | |   | |   ||         | |   | |   | |   ||         | |   | |   | |   | ---         ---   ---       |   |     | |   |     | |   ||   |     | |   |     | |   ||   |     | |   |     | |   | ---         ---   ---   ---*///方法貌似搓了点，但是速度还可以#include <iostream>#include <string>#include <string.h>#include <map>#include <stdio.h>#include <algorithm>#include <queue>#include <vector>#include <math.h>#include <set>#define Max(a,b) ((a)>(b)?(a):(b))#define Min(a,b) ((a)<(b)?(a):(b))#define Max_S 12using namespace std;int S;string NumStr;char Matrix[2*Max_S + 3][(Max_S + 3)*8];//存放LCD显示数字，初始化全部为空格//从上向下，从左向右，分成7笔画，分别为f1至f7void f1(int k){    for(int i = 2;i <= S + 1;i++)    {        Matrix[1][i + (S + 3)*k] = '-';    }}void f2(int k){    for(int i = 2;i <= S + 1;i++)    {        Matrix[i][1 + (S + 3)*k] = '|';    }}void f3(int k){    for(int i = 2;i <= S + 1;i++)    {        Matrix[i][S + 2 + (S + 3)*k] = '|';    }}void f4(int k){    for(int i = 2;i <= S + 1;i++)    {        Matrix[S + 2][i + (S + 3)*k] = '-';    }}void f5(int k){    for(int i = S + 3;i <= 2*S + 2;i++)    {        Matrix[i][1 + (S + 3)*k] = '|';    }}void f6(int k){    for(int i = S + 3;i <= 2*S + 2;i++)    {        Matrix[i][S + 2 + (S + 3)*k] = '|';    }}void f7(int k){    for(int i = 2;i <= S + 1;i++)    {        Matrix[2*S + 3][i + (S + 3)*k] = '-';    }}//初始化Maxtrixvoid init(){    for(int i = 1;i <= 2*S + 3;i++)        {            for(int j = 1;j <= (S + 3)*8 - 1;j++)            {                Matrix[i][j] = ' ';            }        }}//将数字字符转换成LCD显示，每个数字由对应笔画组成void Change(char ch,int k){    switch(ch)    {        case '0':{f1(k);f2(k);f3(k);f5(k);f6(k);f7(k);break;}        case '1':{f3(k);f6(k);break;}        case '2':{f1(k);f3(k);f4(k);f5(k);f7(k);break;}        case '3':{f1(k);f3(k);f4(k);f6(k);f7(k);break;}        case '4':{f2(k);f3(k);f4(k);f6(k);break;}        case '5':{f1(k);f2(k);f4(k);f6(k);f7(k);break;}        case '6':{f1(k);f2(k);f4(k);f5(k);f6(k);f7(k);break;}        case '7':{f1(k);f3(k);f6(k);break;}        case '8':{f1(k);f2(k);f3(k);f4(k);f5(k);f6(k);f7(k);break;}        case '9':{f1(k);f2(k);f3(k);f4(k);f6(k);f7(k);break;}    }}//显示整个数字void Print(){        for(int i = 1;i <= 2*S + 3;i++)        {            for(int j = 1;j <= (S + 3)*NumStr.length() - 1;j++)            {                printf("%c",Matrix[i][j]);            }            printf("\n");        }}int main(){    while(cin>>S>>NumStr,S != 0)    {        init();        for(int i = 0;i < NumStr.length();i++)        {            Change(NumStr[i],i);        }        Print();        printf("\n");    }    return 0;}