ZOJ 3488 Kagome Kagome
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题目链接:ZOJ 3488 Kagome Kagome
围成一个圈,那么知道对面是谁加上半圈的人数就知道背后的是谁了。如果加完大于最大编号要减一下,或者取余。
#include <iostream>#include <cstdio>#include <cstring>using namespace std;const int MAX_N = 100 + 10;const int MAX_M = 20 + 2;char names[MAX_N][MAX_M];int main(){ int T; cin >> T; while(T--) { int n, dist; char name[MAX_M]; cin >> n >> name; for(int i = 0; i < n; i++) { cin >> names[i]; if(strcmp(names[i], name) == 0) dist = i; } int res = dist + (n / 2); if(res >= n) res -= n; cout << names[res] << endl; } return 0;}
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