POJ 1658 解题报告

来源:互联网 发布:linux paraview 编辑:程序博客网 时间:2024/04/19 23:32

也没啥好说的。

1658Accepted132K0MSC++787B

/* ID: thestor1 LANG: C++ TASK: poj1658 */#include <iostream>#include <fstream>#include <cmath>#include <cstdio>#include <cstring>#include <limits>#include <string>#include <vector>#include <list>#include <set>#include <map>#include <queue>#include <stack>#include <algorithm>#include <cassert>using namespace std;int main(){int t;scanf("%d", &t);int nums[4];for (int k = 0; k < t; ++k){for (int i = 0; i < 4; ++i){scanf("%d", &nums[i]);printf("%d ", nums[i]);}if (nums[1] - nums[0] == nums[2] - nums[1] && nums[2] - nums[1] == nums[3] - nums[2]){printf("%d\n", nums[3] + nums[1] - nums[0]);}else{printf("%d\n", nums[3] * nums[1] / nums[0]);}}return 0;  }


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