Compare Version Numbers --- LeetCode
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Compare two version numbers version1 and version1.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.
You may assume that the version strings are non-empty and contain only digits and the .
character.
The .
character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5
is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.
Here is an example of version numbers ordering:
0.1 < 1.1 < 1.2 < 13.37
解题思路:以“.”为分隔符将版本号分为字符串数组,然后将两个数组中从下标为0开始的字符串进行比较。
public class Solution {
public int compare(String v1,String v2){
while(v1.startsWith("0")&&v1.length()>1){
v1=v1.substring(1);
}
while(v2.startsWith("0")&&v2.length()>1){
v2=v2.substring(1);
}
int len1=v1.length();
int len2=v2.length();
if(len1>len2){
return 1;
}
if(len1<len2){
return -1;
}
for(int i=0;i<len1;i++){
char ch1=v1.charAt(i);
char ch2=v2.charAt(i);
if(ch1>ch2){
return 1;
}
if(ch1<ch2){
return -1;
}
}
return 0;
}
public int compareVersion(String version1, String version2) {
String [] v1=version1.split("\\.");
String [] v2=version2.split("\\.");
int v1Len=v1.length;
int v2Len=v2.length;
int len=v1Len<=v2Len?v1Len:v2Len;
int i=0;
for(;i<len;i++){
int rs=compare(v1[i],v2[i]);
if(rs!=0){
return rs;
}
}
if(v1Len>v2Len){
for(;i<v1Len;i++){
if(Integer.valueOf(v1[i])!=0){
return 1;
}
}
}
if(v1Len<v2Len){
for(;i<v2Len;i++){
if(Integer.valueOf(v2[i])!=0){
return -1;
}
}
}
return 0;
}
}
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