第 21、22 讲【项目 4-点和距离】

来源：互联网发布：农村淘宝创始人是谁编辑：程序博客网时间：2024/04/25 22:50

问题描述：

读程序，写出函数的定义，注意其中枚举类型的用法

程序代码：

#include<iostream>using namespace std;enum SymmetricStyle {axisx,axisy,point};//分别表示按 x轴, y轴, 原点对称struct Point{    double x; // 横坐标    double y; // 纵坐标};double distance(Point p1, Point p2); // 两点之间的距离double distance0(Point p1);Point symmetricAxis(Point p,SymmetricStyle style); //返回对称点int main( ){    Point p1= {1,5},p2= {4,1},p;    cout<<"两点的距离为："<<distance(p1,p2)<<endl;    cout<<"p1 到原点的距离为："<<distance0(p1)<<endl;    p=symmetricAxis(p1,axisx);    cout<<"p1 关于 x 轴的对称点为："<<"("<<p.x<<", "<<p.y<<")"<<endl;    p=symmetricAxis(p1,axisy);    cout<<"p1 关于 y 轴的对称点为："<<"("<<p.x<<", "<<p.y<<")"<<endl;    p=symmetricAxis(p1,point);    cout<<"p1 关于原点的对称点为："<<"("<<p.x<<", "<<p.y<<")"<<endl;    return 0;}// 求两点之间的距离double distance(Point p1,Point p2){    double d;    ……    return d;}// 求点到原点的距离double distance0(Point p){    double d;    ……    return d;}// 求对称点Point symmetricAxis(Point p1,SymmetricStyle style){    Point p;    ……    return p;}

解决后代码：

#include<iostream>#include<cmath>using namespace std;enum SymmetricStyle {axisx,axisy,point};//分别表示按 x轴, y轴, 原点对称struct Point{    double x; // 横坐标    double y; // 纵坐标};double distancex(Point p1, Point p2); // 两点之间的距离double distance0(Point p1);Point symmetricAxis(Point p,SymmetricStyle style); //返回对称点int main( ){    Point p1= {1,5},p2= {4,1},p;    cout<<"两点的距离为："<<distance(p1,p2)<<endl;    cout<<"p1 到原点的距离为："<<distance0(p1)<<endl;    p=symmetricAxis(p1,axisx);    cout<<"p1 关于 x 轴的对称点为："<<"("<<p.x<<", "<<p.y<<")"<<endl;    p=symmetricAxis(p1,axisy);    cout<<"p1 关于 y 轴的对称点为："<<"("<<p.x<<", "<<p.y<<")"<<endl;    p=symmetricAxis(p1,point);    cout<<"p1 关于原点的对称点为："<<"("<<p.x<<", "<<p.y<<")"<<endl;    return 0;}// 求两点之间的距离double distancex(Point p1,Point p2){    double d;    d=sqrt((p1.x-p2.x)*(p1.x-p2.x)+(p1.y-p2.y)*(p1.y-p2.y));    return d;}// 求点到原点的距离double distance0(Point p){    double d;    d=sqrt(p.x*p.x+p.y*p.y);    return d;}// 求对称点Point symmetricAxis(Point p1,SymmetricStyle style){    Point p;    p.x=p1.x;    p.y=p1.y;    switch(style)    {    case axisx:        p.y=-p1.y;        break;    case axisy:        p.x=-p1.x;        break;    case point:        p.x=-p1.x;        p.y=-p1.y;        break;    }    return p;}

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