android EditText 输入过滤表情

来源：互联网发布：永恒矩阵编辑：程序博客网时间：2024/04/20 13:18

由于编码原因服务器端是不能识别大部分表情的但是在手机端用搜狗或者百度输入法是可以输入表情的但是我们有不希望用户输入表情

不是当这些表情传入服务器端的时候服务器会报错这就需要我们android过滤了

下面是我写的EditText 输入过滤的

public class Test {        private EditText feed_advise;    //输入表情前EditText中的文本    private String tmp;    //是否重置了EditText的内容    private boolean resetText;    private TextWatcher watcher = new TextWatcher() {        @Override        public void onTextChanged(CharSequence s, int start, int before, int count) {            if(!resetText && start<s.length()) {<span style="color:#808080;">//s<str.length()判断用户是否是删除了输入的数据</span>                char codePoint = s.charAt(start);                if(isEmojiCharacter(codePoint)){                    resetText = true;                    //是表情符号就将文本还原为输入表情符号之前的内容                    feed_advise.setText(tmp);                    feed_advise.setSelection(tmp.length());//设置EditText光标                    <span style="background-color:#344134;">Toast</span>.makeText(Test .<span style="color:#cc7832;">this,</span><span style="color:#6a8759;">"不支持表情输入"</span><span style="color:#cc7832;">,</span><span style="background-color:#344134;">Toast</span>.<span style="color:#9876aa;font-style:italic;">LENGTH_SHORT</span>)<span style="color:#cc7832;">;</span>                }            }else{                resetText = false;            }        }        @Override        public void beforeTextChanged(CharSequence s, int start, int count, int after) {            if(!resetText || s.toString().length()<=start) {<span style="color:#808080;">//s.toString().length()<=start 判断用户是否是删除了输入的数据</span>                tmp = s.toString();//存储这次输入后的文本   好在现场输入表情后还原文本            }        }        @Override        public void afterTextChanged(Editable s) {        }    };    @Override    protected void onCreate(Bundle savedInstanceState) {        super.onCreate(savedInstanceState);        setContentView(R.layout.activity_feed_back);        feed_advise= (EditText) findViewById(R.id.feed_advise);//获取EditText控件        feed_advise.addTextChangedListener(watcher);//设置判断            }     /**     * 是否包含表情     *     * @param codePoint     * @return 如果不包含 返回false,包含 则返回true     */    private static boolean isEmojiCharacter(char codePoint) {        return !((codePoint == 0x0) || (codePoint == 0x9) || (codePoint == 0xA)                || (codePoint == 0xD)                || ((codePoint >= 0x20) && (codePoint <= 0xD7FF))                || ((codePoint >= 0xE000) && (codePoint <= 0xFFFD)) || ((codePoint >= 0x10000) && (codePoint <= 0x10FFFF)));    }}

这个过滤的主要思路是用户输入一个就去判断一下

下面是一个用于过滤一个字符串的表情的代码下面代码的思路是用户输入完全部在去判断用户是否输入表情如果有就把表情去掉

public class EmojiFilter {/*** 是否包含表情* * @param codePoint* @return 如果不包含 返回false,包含 则返回true*/private static boolean isEmojiCharacter(char codePoint) {return !((codePoint == 0x0) || (codePoint == 0x9) || (codePoint == 0xA)|| (codePoint == 0xD)|| ((codePoint >= 0x20) && (codePoint <= 0xD7FF))|| ((codePoint >= 0xE000) && (codePoint <= 0xFFFD)) || ((codePoint >= 0x10000) && (codePoint <= 0x10FFFF)));}/*** 过滤emoji 或者 其他非文字类型的字符* * @param source* @return*/public static String filterEmoji(String source) {StringBuilder buf = null;int len = source.length();for (int i = 0; i < len; i++) {char codePoint = source.charAt(i);if (!isEmojiCharacter(codePoint)) {// 如果不包含 则将字符appendif (buf == null) {buf = new StringBuilder(source.length());}buf.append(codePoint);} else {}}if (buf == null) {return source;// 如果没有找到 emoji表情，则返回源字符串} else {if (buf.length() == len) {// 这里的意义在于尽可能少的toString，因为会重新生成字符串buf = null;return source;} else {return buf.toString();}}}}

本文有一部分引用于http://download.csdn.net/detail/ycxyyzw/8550353 demo代码

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