HDU 2055 An easy problem

Problem Description

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

 

Input

On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.

 

Output

for each case, you should the result of y+f(x) on a line.

 

Sample Input

6R 1P 2G 3r 1p 2g 3

 

Sample Output

191810-17-14-4
水题，上代码：
#include<stdio.h>int main(){int n,b;char a;while(scanf("%d",&n)!=EOF){while(n--){getchar();scanf("%c%d",&a,&b);if(a>='a'&&a<='z')printf("%d\n",-(a-'a'+1)+b);elseprintf("%d\n",a-'A'+1+b);}}return 0;}