hdoj-1212-Big Number【大数取余&简单题】

Big Number

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 6015 Accepted Submission(s): 4205

Problem Description

As we know, Big Number is always troublesome. But it's really important in our ACM. And today, your task is to write a program to calculate A mod B.

To make the problem easier, I promise that B will be smaller than 100000.

Is it too hard? No, I work it out in 10 minutes, and my program contains less than 25 lines.

Input

The input contains several test cases. Each test case consists of two positive integers A and B. The length of A will not exceed 1000, and B will be smaller than 100000. Process to the end of file.

Output

For each test case, you have to ouput the result of A mod B.

Sample Input

2 312 7152455856554521 3250

Sample Output

251521

Author

Ignatius.L

Source

杭电ACM省赛集训队选拔赛之热身赛

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#include<stdio.h> #include<string.h>int main(){int b;char a[1010];while(~scanf("%s%d",a,&b)){ int len=strlen(a),res=0; for(int i=0;i<len;++i){ res=res*10+a[i]-'0'; if(res>=b)  res=res%b; }     printf("%d\n",res);}return 0;}