# 题目

### Length of Last Word

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Given a string s consists of upper/lower-case alphabets and empty space characters `' '`, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,
Given s = `"Hello World"`,
return `5`.

# 解析

`class Solution {public:    int lengthOfLastWord(string s) {        int i = s.size()-1;int ret = 0;while ( i>=0 && s[i] == ' ') i--; while (i>=0 && s[i]!=' ') { i--; ret++; } return ret;    }};`

`public:int lengthOfLastWord(const char *s) {  const string str(s);  auto first = find_if(str.rbegin(), str.rend(), ::isalpha);  auto last = find_if_not(first, str.rend(), ::isalpha);  return distance(first, last); }};`

`class Solution {public:int lengthOfLastWord(const char *s) {  int len = 0;  while (*s) {   if (*s++ != ' ')   ++len;  else if (*s && *s != ' ')     len = 0;  }  return len;}};`

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