leetcode 058 Length of Last Word（难易度：Easy）

Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,
Given s = "Hello World",
return 5.

代码：

int lengthOfLastWord(char* s) {    if(s == NULL || *s == '\0')        return 0;    int len = strlen(s);    int index = len - 1;    int lengthoflastword = 0;    while(index >= 0 && s[index] == ' ')        index --;    while (index >= 0 && s[index] != ' ')    {        lengthoflastword ++;        index --;    }    return lengthoflastword;}

原题地址：https://leetcode.com/problems/length-of-last-word/