万年历（C语言代码实现）

学了一个学期的C，由于C语言基础不扎实，所以重新学习了一次。参考了一部分网上代码，按照框架思路自己再编写了程序代码。只是简单万年历功能的实现。一些不足之处，还请多多包涵~~

#include <stdio.h>#include <windows.h> enum weekday { Sun, Mon, Jue, Wed, Thu, Fri, Sat };enum month { January = 1, February, Match, Apirl, May, June, July, August, September, October, November, December };void color(int a)  //颜色函数 {SetConsoleTextAttribute(GetStdHandle(STD_OUTPUT_HANDLE), a);}void printMonthHeader(void)  //输出日历每个月份的表头{printf("周日周一周二周三周四  周五  周六\n");}int judgeYear(int Y)  //判断平年闰年，若为平年则为 0，闰年为 1{enum differentYear{ nonleapYear, leapYear };return ( Y % ( Y % 100 ? 4:400) ? nonleapYear : leapYear);}void printMonth( int firstDay, int days )  //输出每个月份的日历表，firstDay是每个月的第一天，days是一个月的总天数{int position = firstDay;int i;printMonthHeader();for( i = 0; i < position; ++i ){printf("");}for( i = 1; i <= days; ++i ){position = (++position) % 7;printf("%-7d", i);if(position == 0)printf("\n");}printf("\n");}int firstDayOfYear(const int getYear)  //计算一年中第一天是周几 {int weekDay;weekDay = ( (getYear - 1) + (getYear - 1) / 4 - (getYear / 100) + (getYear / 400) + 1 ) % 7;return weekDay;}void printfYear(const int year){weekday yDay = (enum weekday)(firstDayOfYear(year));//计算一年的第一天是周几int aDay = judgeYear(year);//判断平年闰年，若为平年则为0，闰年为1int monDays[13];//每个月的天数int monFirstday[13];//计算每个月的第一天是周几monDays[January] = 31;monDays[February]=28+aDay;monDays[Match]=31;  monDays[Apirl]=30;monDays[May]=31;monDays[June]=30;  monDays[July]=31;monDays[August]=31;monDays[September]=30;  monDays[October]=31;monDays[November]=30;monDays[December]=31;  monFirstday[0]=0;  monFirstday[January]   = yDay;  monFirstday[February]  = ((monFirstday[January]    +monDays[January]    )%7);  monFirstday[Match]     = ((monFirstday[February]   +monDays[February]   )%7);  monFirstday[Apirl]     = ((monFirstday[Match]      +monDays[Match]      )%7);  monFirstday[May]       = ((monFirstday[Apirl]      +monDays[Apirl]      )%7);  monFirstday[June]      = ((monFirstday[May]        +monDays[May]        )%7);  monFirstday[July]      = ((monFirstday[June]       +monDays[June]       )%7);  monFirstday[August]    = ((monFirstday[July]       +monDays[July]       )%7);  monFirstday[September] = ((monFirstday[August]     +monDays[August]     )%7);  monFirstday[October]   = ((monFirstday[September]  +monDays[September]  )%7);  monFirstday[November]  = ((monFirstday[October]    +monDays[October]    )%7);  monFirstday[December]  = ((monFirstday[November]   +monDays[November]   )%7); int j;for( j = January; j <= December; ++j ){printf("\n*******************************************************************\n\n");printf("                   %d     %d                         \n\n", year, j);printMonth(monFirstday[j], monDays[j]);printf("\n");}return;}int main(){color(11);int quit = 0;int year = 0;do{printf("请输入您想查询的年份（选择0退出):     ");scanf("%d", &year);printf("\n");if( year == 0 )quit = 1;elseprintfYear(year);}while(!quit);return 0;}//大概每四年一个闰年，所以可计算：//  公元一年到公元 year-1 年内的闰年个数 = (year - 1) / 4//但是每一百年要扣掉一个闰年，所以修正后：//  公元一年到公元 year-1 年内的闰年个数 = (year - 1) / 4 - (year / 100) //其实每四百年又要增加一个闰年，再次修正：//  公元一年到公元 year-1 年内的闰年个数 = (year - 1) / 4 - (year / 100) + (year / 400)//一年的第一天距离起始天的差是：//  (year - 1)*365 + (公元一年到公元year-1年内的闰年个数（每个闰年多一天）)//故得到//  (year - 1)*365 + (year - 1) / 4 - (year / 100) + (year / 400)//这天是周几//  [(year - 1)*365 + (year - 1) / 4 - (year / 100) + (year / 400)] % 7 + 1//  = [(year - 1)*365 + (year - 1) / 4 - (year / 100) + (year / 400) + 1] % 7 //  = [(year - 1)*364 + (year - 1) + (year - 1) / 4 - (year / 100) + (year / 400) + 1] % 7//  = [ (year - 1) + (year - 1) / 4 - (year / 100) + (year / 400) + 1 ] % 7