开启3个线程,这3个线程的ID分别为A、B、C,每个线程将自己的ID在屏幕上,要求输出结果必须按ABC的顺序显示:ABCABC【转载】

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题目:

编写一个程序,开启3个线程,这3个线程的ID分别为A、B、C,每个线程将自己的ID在屏幕上打印10遍,要求输出结果必须按ABC的顺序显示;如:ABCABC….依次递推。

代码实现:

#include <stdio.h>   #include <process.h>   #include <windows.h>   #define  g_hThreadEvent(n) g_hThreadEvent##1unsigned int __stdcall Fun(void *pPM);  //线程个数const int THREAD_NUM = 8;  //循环次数const int LOOP = 6;//互斥事件HANDLE g_hThreadEvent[THREAD_NUM];int main(){    printf("\t子线程循环 10 次,接着主线程循环 100 次,接着又回到子线程循环10 次,\n接着再回到主线程又循环 100 次,如此循环50次\n");    int i = 0 , j;    HANDLE hdl[THREAD_NUM];    for (i = 0; i < THREAD_NUM; i++)         g_hThreadEvent[i] = CreateEvent(NULL,FALSE,FALSE,NULL);    //将线程编号作为线程参数传进去,先转换为指针,再转换为整形,    for (i = 0; i < THREAD_NUM; i++)         hdl[i] = (HANDLE)_beginthreadex(NULL,0,Fun,(void*)i,0,NULL);    SetEvent(g_hThreadEvent[0] );    WaitForMultipleObjects(THREAD_NUM,hdl,TRUE,INFINITE);    for (i = 0; i < THREAD_NUM; i++)    {        CloseHandle(hdl[i]);        CloseHandle(g_hThreadEvent[i]);    }    return 0;}unsigned int __stdcall Fun(void *pPM){    int num = (int)pPM;    int i = 0;    for( i  = 0 ; i< LOOP;i++)    {        WaitForSingleObject(g_hThreadEvent[num],INFINITE);        //printf("  线程ID=%d,线程编号是%c ,%d \n",GetCurrentThreadId(),num+'A');            printf(" %c ",num+'A');         if(num+1 == THREAD_NUM )             printf(" \n");        SetEvent(g_hThreadEvent[(num+1)%THREAD_NUM]);    }    return 0;}

运行效果
运行效果

原创地址(谢谢博主的无私分享):
http://blog.csdn.net/lilien1010/article/details/8118735

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