226. Invert Binary Tree

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Invert a binary tree.

     4   /   \  2     7 / \   / \1   3 6   9
to
     4   /   \  7     2 / \   / \9   6 3   1
Trivia:
This problem was inspired by this original tweet by Max Howell:
Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so fuck off.
/** * Definition for a binary tree node. * struct TreeNode { *     int val; *     TreeNode *left; *     TreeNode *right; *     TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */class Solution {public:    TreeNode* invertTree(TreeNode* root)     {                if(!root)            return NULL;        if(!root->left&&!root->right)                return root;        TreeNode* y=root->right;        root->right=invertTree(root->left);        root->left=invertTree(y);        return root;        }};

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