nyoj 1242 Interference Signal (河南省第八届acm程序设计大赛)

来源:互联网 发布:果戈里大街知乎 编辑:程序博客网 时间:2024/04/19 17:13
  • 题目1242
  • 题目信息
  • 运行结果
  • 本题排行
  • 讨论区

Interference Signal

时间限制:2000 ms  |  内存限制:65535 KB
难度:1
描述

Dr.Kong’s laboratory monitor some interference signals. The interference signals can be digitized into a series of positive integer. May be, there areN integers a1,a2,…,an.

 

Dr.Kong wants to know the average strength of a contiguous interference signal block.the block must contain at least M integers.

 

Please help Dr.Kong to calculate themaximum average strength, given the constraint.

输入
The input contains K test cases. Each test case specifies:
* Line 1: Two space-separated integers, N and M.
* Lines2~line N+1: ai (i=1,2,…,N)
1 ≤ K≤ 8, 5 ≤ N≤ 2000, 1 ≤ M ≤ N, 0 ≤ ai ≤9999
输出
For each test case generate a single line containing a single integer that is 1000 times the maximal average value. Do not perform rounding.
样例输入
2 10 66 42103859415 210385 9 
样例输出
65007333
来源
第八届河南省程序设计大赛
上传者

hnu_acm

两个注意点 一个是at least 一个是 Do not perform rounding.

#include <stdio.h>#include <string.h>int main(){int ncase,a[2005];scanf("%d",&ncase);while(ncase--){int n,m;double sum,max=-0x3fffffff;memset(a,0,sizeof(a));scanf("%d %d",&n,&m);for(int i=0;i<n;i++)scanf("%d",&a[i]);for(int i=0;i+m<=n;i++){for(int k=m;k<=n&&i+k<=n;k++){sum=0;for(int j=0;j<k;j++)sum+=a[i+j];if(sum/k>max)max=sum/k;}}printf("%d\n",(int)(max*1000));}return 0;}


0 0
原创粉丝点击