260. Single Number III
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解法一:
public class Solution { public int[] singleNumber(int[] nums) { int[] copyNum = new int[nums.length];LinkedList<Integer> list = new LinkedList<Integer>();for (int i : nums) {if (list.contains(i)) {list.remove(list.indexOf(i));}else {list.add(i);}}int res[] = new int[2];res[0] = list.pop();res[1] = list.pop();return res; }}
解法二:
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- 260.Single Number III
- 260. Single Number III
- 260. Single Number III
- 260. Single Number III
- 260. Single Number III
- 260. Single Number III
- 260. Single Number III
- 260. Single Number III
- 260. Single Number III
- 260. Single Number III
- 260. Single Number III
- 260. Single Number III
- 260. Single Number III
- 260. Single Number III
- 260. Single Number III
- 260. Single Number III
- 260. Single Number III
- 260. Single Number III
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