完整详解GCD系列（四）dispatch_semaphore（信号量）

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完整详解GCD系列（四）dispatch_semaphore（信号量）

阅读：2887 时间：2015-01-09 20:28

原创Blog，转载请注明出处

http://blog.csdn.net/hello_hwc?viewmode=contents

一何为信号量？

简单来说就是控制访问资源的数量，比如系统有两个资源可以被利用，同时有三个线程要访问，只能允许两个线程访问，第三个应当等待资源被释放后再访问。

注意：再GCD中，只有调度的线程在信号量不足的时候才会进入内核态进行线程阻塞

二如何使用信号量

三个主要函数

创建一个信号量

func dispatch_semaphore_create(_ value: Int) ->  dispatch_semaphore_t !

其中value为信号量的初值，如果小于0则会返回NULL

提高信号量

func dispatch_semaphore_signal(_ dsema: dispatch_semaphore_t!) -> Int

等待降低信号量

func dispatch_semaphore_wait(_ dsema: dispatch_semaphore_t!,                           _ timeout: dispatch_time_t) -> Int

注意，正常的使用顺序是先降低然后再提高，这两个函数通常成对使用。

三举例分析

<pre name="code" class="objc">////  ViewController.swift//  SwiftTestExample////  Created by huangwenchen on 15/1/6.//  Copyright (c) 2015年 huangwenchen. All rights reserved.//import UIKitclass ViewController: UIViewController {    var semaphore:dispatch_semaphore_t;    required init(coder aDecoder: NSCoder) {        self.semaphore = dispatch_semaphore_create(1)        super.init(coder: aDecoder)    }    override func viewDidLoad() {        super.viewDidLoad()        dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT,0), {() -> Void  in             self.task_first()        })        dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT,0), { () -> Void in            self.task_second()        })        dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT,0), { () -> Void in            self.task_third()        })        // Do any additional setup after loading the view, typically from a nib.    }    func task_first(){        dispatch_semaphore_wait(self.semaphore, DISPATCH_TIME_FOREVER)        NSLog("%@","First task starting")        sleep(1)        NSLog("%@", "First task is done")        dispatch_semaphore_signal(self.semaphore)    }    func task_second(){        dispatch_semaphore_wait(self.semaphore, DISPATCH_TIME_FOREVER)        NSLog("%@","Second task starting")        sleep(1)        NSLog("%@", "Second task is done")        dispatch_semaphore_signal(self.semaphore)    }    func task_third(){        dispatch_semaphore_wait(self.semaphore, DISPATCH_TIME_FOREVER)        NSLog("%@","Thrid task starting")        sleep(1)        NSLog("%@", "Thrid task is done")        dispatch_semaphore_signal(self.semaphore)    }    override func didReceiveMemoryWarning() {        super.didReceiveMemoryWarning()        // Dispose of any resources that can be recreated.    }}

这段代码模拟提交三个任务，提交到全局队列（并行队列）

当信号量的初初始为2时候

输出

2015-01-06 19:42:01.963 SwiftTestExample[632:11631] First task starting2015-01-06 19:42:01.964 SwiftTestExample[632:11630] Second task starting2015-01-06 19:42:02.971 SwiftTestExample[632:11630] Second task is done2015-01-06 19:42:02.971 SwiftTestExample[632:11631] First task is done2015-01-06 19:42:02.971 SwiftTestExample[632:11633] Thrid task starting2015-01-06 19:42:03.974 SwiftTestExample[632:11633] Thrid task is done

当信号量为3的时候

2015-01-06 19:42:49.912 SwiftTestExample[666:12259] First task starting2015-01-06 19:42:49.912 SwiftTestExample[666:12258] Second task starting2015-01-06 19:42:49.912 SwiftTestExample[666:12260] Thrid task starting2015-01-06 19:42:50.915 SwiftTestExample[666:12259] First task is done2015-01-06 19:42:50.915 SwiftTestExample[666:12260] Thrid task is done2015-01-06 19:42:50.915 SwiftTestExample[666:12258] Second task is done

当信号量为1的时候

2015-01-06 19:43:35.140 SwiftTestExample[694:12768] First task starting2015-01-06 19:43:36.145 SwiftTestExample[694:12768] First task is done2015-01-06 19:43:36.145 SwiftTestExample[694:12771] Second task starting2015-01-06 19:43:37.146 SwiftTestExample[694:12771] Second task is done2015-01-06 19:43:37.146 SwiftTestExample[694:12769] Thrid task starting2015-01-06 19:43:38.150 SwiftTestExample[694:12769] Thrid task is done

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