POJ-1094-Sorting It All Out(拓扑排序)
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Sorting It All Out
Time Limit: 1000MS Memory Limit: 10000KTotal Submissions: 32037 Accepted: 11131
Description
An ascending sorted sequence of distinct values is one in which some form of a less-than operator is used to order the elements from smallest to largest. For example, the sorted sequence A, B, C, D implies that A < B, B < C and C < D. in this problem, we will give you a set of relations of the form A < B and ask you to determine whether a sorted order has been specified or not.
Input
Input consists of multiple problem instances. Each instance starts with a line containing two positive integers n and m. the first value indicated the number of objects to sort, where 2 <= n <= 26. The objects to be sorted will be the first n characters of the uppercase alphabet. The second value m indicates the number of relations of the form A < B which will be given in this problem instance. Next will be m lines, each containing one such relation consisting of three characters: an uppercase letter, the character "<" and a second uppercase letter. No letter will be outside the range of the first n letters of the alphabet. Values of n = m = 0 indicate end of input.
Output
For each problem instance, output consists of one line. This line should be one of the following three:
Sorted sequence determined after xxx relations: yyy...y.
Sorted sequence cannot be determined.
Inconsistency found after xxx relations.
where xxx is the number of relations processed at the time either a sorted sequence is determined or an inconsistency is found, whichever comes first, and yyy...y is the sorted, ascending sequence.
Sorted sequence determined after xxx relations: yyy...y.
Sorted sequence cannot be determined.
Inconsistency found after xxx relations.
where xxx is the number of relations processed at the time either a sorted sequence is determined or an inconsistency is found, whichever comes first, and yyy...y is the sorted, ascending sequence.
Sample Input
4 6A<BA<CB<CC<DB<DA<B3 2A<BB<A26 1A<Z0 0
Sample Output
Sorted sequence determined after 4 relations: ABCD.Inconsistency found after 2 relations.Sorted sequence cannot be determined.
Source
East Central North America 2001
注意:判断 1,构成环 2,有序 3,无序。
1,2成立立刻无视后续数据输出。
//#include <bits/stdc++.h>#include <cstring>#include <iostream>#include <algorithm>#include <cstdio>using namespace std;int Scan(){ int res=0,ch,flag=0; if((ch=getchar())=='-')flag=1; else if(ch>='0'&&ch<='9')res=ch-'0'; while((ch=getchar())>='0'&&ch<='9')res=res*10+ch-'0'; return flag?-res:res;}void Out(int a){if(a>9)Out(a/10);putchar(a%10+'0');}int n,m;char str[5];int map_[30][30],in[30],p[30],stack_[30];int TopoSort(){ memcpy(p,in,sizeof(in)); int top=0,flag=1; for(int i=1; i<=n; ++i) { int temp=0,poi; for(int j=1; j<=n; ++j) if(p[j]==0){temp++; poi=j;} if(!temp)return 0;//构成环 if(temp>1)flag=-1;//无序 stack_[top++]=poi; p[poi]=-1; for(int j=1; j<=n; ++j) if(map_[poi][j])p[j]--; } return flag;//有序}int main(){ while(scanf("%d%d",&n,&m)!=EOF) { if(!n||!m)break; memset(in,0,sizeof(in)); memset(map_,0,sizeof(map_)); int flag=0; for(int i=1; i<=m; ++i) { scanf("%s",str); if(flag)continue; int a=str[0]-'A'+1; int b=str[2]-'A'+1; map_[a][b]=1; ++in[b]; int poi=TopoSort(); if(poi==0) { printf("Inconsistency found after %d relations.\n",i); flag=1; } else if(poi==1) { printf("Sorted sequence determined after %d relations: ",i); for(int j=0;j<n;j++) printf("%c",stack_[j]+'A'-1); printf(".\n"); flag=1; } } if(!flag)printf("Sorted sequence cannot be determined.\n"); } return 0;}
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