Leetcode 58. Length of Last Word (Easy) (cpp)

Leetcode 58. Length of Last Word (Easy) (cpp)

Tag: String

Difficulty: Easy

/*58. Length of Last Word (Easy)Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.If the last word does not exist, return 0.Note: A word is defined as a character sequence consists of non-space characters only.For example, Given s = "Hello World",return 5.*/class Solution {public:int lengthOfLastWord(string s) {int len = s.length() - 1, res = 0;while(len > -1) {if (s[len] != ' ') res++;else if (res) return res;len--;}return res;}};