HDU:2136 Largest prime factor!(素数)
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Largest prime factor
Time Limit: 5000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 11087 Accepted Submission(s): 3913
Problem Description
Everybody knows any number can be combined by the prime number.
Now, your task is telling me what position of the largest prime factor.
The position of prime 2 is 1, prime 3 is 2, and prime 5 is 3, etc.
Specially, LPF(1) = 0.
Now, your task is telling me what position of the largest prime factor.
The position of prime 2 is 1, prime 3 is 2, and prime 5 is 3, etc.
Specially, LPF(1) = 0.
Input
Each line will contain one integer n(0 < n < 1000000).
Output
Output the LPF(n).
Sample Input
12345
Sample Output
01213
Author
Wiskey
Source
HDU 2007-11 Programming Contest_WarmUp
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题目大意:我们知道,每个数都能拆分成素数的乘积的形式,给你一个数字n,问你组成这个数字的素数中最大的素数是谁?输出这个素数的位置。(其中素数2对应的位置为1,素数3对应的位置为2,素数5对应的位置为3,特别的1(虽然不是素数)对应的位置为0.)
解题思路:筛素法。
代码如下:
#include <cstdio>int a[1000010];void dabiao(){a[1]=0;int k=1;for(int i=2;i<1000010;i++){if(a[i]!=0){continue;}a[i]=k;for(int j=i*2;j<1000010;j=j+i){a[j]=k;}k++;}}int main(){dabiao();int n;while(scanf("%d",&n)!=EOF){printf("%d\n",a[n]);}return 0;}
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