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Problem C: 平面上的点——Point类 (III)

Problem C: 平面上的点——Point类 (III)

Time Limit: 1 Sec  Memory Limit: 4 MB
Submit: 4451  Solved: 3063
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Description

在数学上，平面直角坐标系上的点用X轴和Y轴上的两个坐标值唯一确定。现在我们封装一个“Point类”来实现平面上的点的操作。

根据“append.cc”，完成Point类的构造方法和show()方法，输出各Point对象的构造和析构次序。实现showPoint()函数。

接口描述：
showPoint()函数按输出格式输出Point对象，调用Point::show()方法实现。
Point::show()方法：按输出格式输出Point对象。

Input

输入多行，每行为一组坐标“x,y”，表示点的x坐标和y坐标，x和y的值都在double数据范围内。

Output

输出每个Point对象的构造和析构行为。showPoint()函数用来输出（通过参数传入的）Point对象的值：X坐标在前，Y坐标在后，Y坐标前面多输出一个空格。每个坐标的输出精度为最长16位。输出格式见sample。

C语言的输入输出被禁用。

Sample Input

1,2
3,3
2,1

Sample Output

Point : (0, 0) is created.
Point : (1, 2) is created.
Point : (1, 2) is copied.
Point : (1, 2)
Point : (1, 2) is erased.
Point : (1, 2) is erased.
Point : (3, 3) is created.
Point : (3, 3) is copied.
Point : (3, 3)
Point : (3, 3) is erased.
Point : (3, 3) is erased.
Point : (2, 1) is created.
Point : (2, 1) is copied.
Point : (2, 1)
Point : (2, 1) is erased.
Point : (2, 1) is erased.
Point : (0, 0) is copied.
Point : (1, 1) is created.
Point : (0, 0) is copied.
Point : (1, 1) is copied.
Point : (0, 0) is copied.
Point : (0, 0)
Point : (1, 1)
Point : (0, 0)
Point : (0, 0) is erased.
Point : (1, 1) is erased.
Point : (0, 0) is erased.
Point : (1, 1) is erased.
Point : (0, 0) is erased.
Point : (0, 0) is erased.

HINT

思考构造函数、拷贝构造函数、析构函数的调用时机。

Append Code

append.cc,

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