【LEET-CODE】27. Remove Element

Qusetion:

Given an array and a value, remove all instances of that value in place and return the new length.

Do not allocate extra space for another array, you must do this in place with constant memory.

The order of elements can be changed. It doesn't matter what you leave beyond the new length.

Example:
Given input array nums = [3,2,2,3], val = 3

Your function should return length = 2, with the first two elements of nums being 2.

思路：

删除数组中的val，循环比较即可，注意使用erase后使用i--调整标号

Code:

class Solution {public:    int removeElement(vector<int>& nums, int val) {        for(int i = 0;i < nums.size();i++){            if(nums[i] == val){               nums.erase(nums.begin()+i);                i--;            }        }        int length = nums.size();        return length;    }};

Your runtime beats 76.31% of cpp submissions