poj 3468 A Simple Problem with Integers

来源:互联网 发布:淘宝客服招聘网 编辑:程序博客网 时间:2024/05/16 11:51

Description

You have N integers, A1A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given number to each number in a given interval. The other is to ask for the sum of numbers in a given interval.

Input

The first line contains two numbers N and Q. 1 ≤ N,Q ≤ 100000.
The second line contains N numbers, the initial values of A1A2, ... , AN. -1000000000 ≤ Ai ≤ 1000000000.
Each of the next Q lines represents an operation.
"C a b c" means adding c to each of AaAa+1, ... , Ab. -10000 ≤ c ≤ 10000.
"Q a b" means querying the sum of AaAa+1, ... , Ab.

Output

You need to answer all Q commands in order. One answer in a line.

Sample Input

10 51 2 3 4 5 6 7 8 9 10Q 4 4Q 1 10Q 2 4C 3 6 3Q 2 4

Sample Output

455915

线段树的区间更新,用到了延时更新标记,很难调啊

#include <stdio.h>#define N 100001#define ll long long#define lson l,m,rt<<1#define rson m+1,r,rt<<1|1ll add[N<<2];ll sum[N<<2];void PushUP(int rt){    sum[rt]=sum[rt<<1]+sum[rt<<1|1];}void PushDown(int rt,int m){    if(add[rt])    {        add[rt<<1]+=add[rt];        add[rt<<1|1]+=add[rt];        sum[rt<<1]+=(m-(m>>1))*add[rt];        sum[rt<<1|1]+=(m>>1)*add[rt];        add[rt]=0;    }}void Build(int l,int r,int rt){    add[rt]=0;    if(l==r)    {        scanf("%I64d",&sum[rt]);        return;    }    int m=(l+r)>>1;    Build(lson);    Build(rson);    PushUP(rt);}void Update(int L,int R,int c,int l,int r,int rt){    if(L<=l&&R>=r)    {        add[rt]+=c;        sum[rt]+=(ll)c*(r-l+1);        return;    }    PushDown(rt,r-l+1);    int m=(l+r)>>1;    if(L<=m)        Update(L,R,c,lson);    if(R>m)        Update(L,R,c,rson);    PushUP(rt);}ll Query(int L,int R,int l,int r,int rt){    if(L<=l&&R>=r)        return sum[rt];    PushDown(rt,r-l+1);    int m=(l+r)>>1;    ll ret=0;    if(L<=m)   ret+=Query(L,R,lson);    if(R>m)    ret+=Query(L,R,rson);    return ret;}int main(){    int m,n;    scanf("%d%d",&n,&m);    Build(1,n,1);    while(m--)    {        char s[5];        int a,b,c;        scanf("%s",s);        if(s[0]=='Q')        {            scanf("%d%d",&a,&b);            printf("%I64d\n",Query(a,b,1,n,1));        }        else        {            scanf("%d%d%d",&a,&b,&c);            Update(a,b,c,1,n,1);        }    }    return 0;}




0 0
原创粉丝点击