Two Sum
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Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twic
vector<int> twoSum(vector<int> &numbers, int target){ unordered_map<int, int> hash; vector<int> result; for (int i = 0; i < numbers.size(); i++) { int numberToFind = target - numbers[i]; if (hash.find(numberToFind) != hash.end()) { result.push_back(hash[numberToFind]); result.push_back(i); } hash[numbers[i]] = i; } return result;}
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