Tree-----镜像树(101. Symmetric Tree)
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原题目
看到树的递归有点心慌慌,但是,。,随意一写就OK了,有的时候太紧张还是不行,一点要慢点
public class Solution { public boolean isSymmetric(TreeNode root) { if (root == null) { return true; } return is(root.left, root.right); } public boolean is(TreeNode a, TreeNode b) { if (a == null && b == null) { return true; } if (a == null || b == null) { return false; } if (a.val != b.val) { return false; } return is(a.left, b.right) && is(a.right, b.left); }}
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