使用Spring的WebAsyncTask异步请求时出错Can't set AsyncWebRequest with concurrent handling in progress

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使用Spring的WebAsyncTask异步请求时出现如下错误：

java.lang.IllegalStateException: Cannot forward after response has been committedjava.lang.IllegalStateException: Can't set AsyncWebRequest with concurrent handling in progressorg.springframework.web.util.NestedServletException: Request processing failed; Caused by: java.lang.IllegalStateException: Can't set AsyncWebRequest with concurrent handling in progress    at org.springframework.util.Assert.state(Assert.java:392)    at org.springframework.web.context.request.async.WebAsyncManager.setAsyncWebRequest(WebAsyncManager.java:108)

表面上看错误描述并不清楚。这里我仅仅记录我的解决方法，我这里是因为时间超时引起的。也许你也是这样的情况：
原代码结结构如下：

@RequestMapping(value = { "/webAsyncTask/test" })    public WebAsyncTask test(HttpServletRequest request) {        Callable<String> callable = new Callable<String>() {            public String call() throws InterruptedException {                String string = new String();                Thread.sleep(15000);                return string;            }        };        return new WebAsyncTask(callable);    }

这里直接返回的new WebAsyncTask(callable)报错。我是通过设置超时时间解决的：返回new WebAsyncTask(60000, callable)；
注意：即使设置里超时时间而没做超时处理，这样是不严谨的。因为当60000毫秒之后call()没执行完依然会报异常。Spring对超时处理提供有WebAsyncTask.onTimeout()方法。
所有我最终的代码结构如下：

@RequestMapping(value = { "/webAsyncTask/test" })    public WebAsyncTask test(HttpServletRequest request) {        Callable<String> callable = new Callable<String>() {            public String call() throws InterruptedException {                String string = new String();                Thread.sleep(15000);                return string;            }        };        WebAsyncTask asyncTask = new WebAsyncTask(60000, callable);        asyncTask.onTimeout(new Callable<String>() {            public String call() throws Exception {                String string = "请求超时!";                return string;            }        });        return asyncTask;    }

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