sdut 3252 Lowest Unique Price

Lowest Unique Price

Time Limit: 1000MS Memory Limit: 65536KB

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Problem Description

Recently my buddies and I came across an idea! We want to build a website to sell things in a new way.

For each product, everyone could bid at a price, or cancel his previous bid, finally we sale the product to the one who offered the “lowest unique price”. The lowest unique price is defined to be the lowest price that was called only once.

So we need a program to find the “lowest unique price”, We’d like to write a program to process the customers’ bids and answer the query of what’s the current lowest unique price.

All what we need now is merely a programmer. We will give you an “Accepted” as long as you help us to write the program.

Input

The first line of input contains an integer T, indicating the number of test cases (T ≤ 60).

Each test case begins with a integer N (1 ≤ N ≤ 200000) indicating the number of operations.

Next N lines each represents an operation.

There are three kinds of operations:

“b x”: x (1 ≤ x ≤ 10^6) is an integer, this means a customer bids at price x.

“c x”: a customer has canceled his bid at price x.

“q” : means “Query”. You should print the current lowest unique price.

Our customers are honest, they won\’t cancel the price they didn’t bid at.

Output

Please print the current lowest unique price for every query (“q”). Print “none” (without quotes) if there is no lowest unique price.

Example Input

2
3
b 2
b 2
q
12
b 2
b 2
b 3
b 3
q
b 4
q
c 4
c 3
q
c 2
q

Example Output

none
none
4
3
2
题意：n次操作，b x，插入值为x的数。c x，删除值为x的数。q 输出出现次数为1且最小的数。
题解：set+map。
代码：

#include<iostream>#include<stdio.h>#include<stdlib.h>#include<algorithm>#include<vector>#include<cmath>#include<set>#include<map>#include<string.h>#define ll long longusing namespace std;int t,n,x;map<int,int>mp;set<int>s;char ss[100];int main(){    scanf("%d",&t);    while(t--)    {        mp.clear();        s.clear();        scanf("%d",&n);        for(int i=0;i<n;i++)        {            scanf("%s",ss);            if(ss[0]=='b')            {                scanf("%d",&x);                mp[x]++;                if(mp[x]==1) s.insert(x);                else s.erase(x);            }            else if(ss[0]=='c')            {                scanf("%d",&x);                mp[x]--;                if(mp[x]==1) s.insert(x);                else s.erase(x);            }            else            {                if(s.empty()) cout<<"none"<<endl;                else                cout<<*s.begin()<<endl;            }        }    }}