1081. Rational Sum 解析
来源:互联网 发布:java项目有红色感叹号 编辑:程序博客网 时间:2024/06/18 15:17
分数的求和,还是规成求最大公因数的问题。
注意讨论各种情况,整数,真分数,假分数。
#include <iostream>using namespace std;int n;long long gcd(long long a, long long b) {if (b == 0) return a;else return gcd(b, a%b);}int main() {cin >> n;long long fra1, num1,fra2,num2;cin >> fra1;cin.get();cin >> num1;for (int i = 1; i < n; i++) {cin >> fra2;cin.get();cin >> num2;fra1 = fra1 * num2 + fra2 * num1;num1 = num1*num2;}if (fra1 == 0) {cout << 0 << endl;return 0;}long long factor = gcd(fra1, num1);fra1 /= factor;num1 /= factor;if (fra1 % num1 == 0) { //整数cout << fra1 / num1 << endl;}else if (fra1 < num1) { //真分数cout << fra1 << "/" << num1 << endl;}else {long long dec = fra1 / num1;fra1 %= num1;cout << dec << " " << fra1 << "/" << num1 << endl;}return 0;}
0 0
- 1081. Rational Sum 解析
- PAT 1081. Rational Sum
- 1081. Rational Sum
- 1081. Rational Sum (20)
- 1081. Rational Sum (20)
- 1081. Rational Sum (20)
- 1081. Rational Sum (20)
- 1081.Rational Sum
- 1081. Rational Sum (20)
- 1081. Rational Sum (20)
- 1081. Rational Sum (20)
- 1081. Rational Sum (20)
- 1081. Rational Sum
- 1081. Rational Sum (20)
- 1081. Rational Sum (20)
- 1081. Rational Sum (20)
- 1081. Rational Sum
- 1081. Rational Sum (20)
- cas 4.2.5 返回更多的用户信息
- 多表透视图的制作 第一讲:数据规范化
- LeetCode之Distribute Candies
- PRVG-10122 : ASMLib configuration value
- redis
- 1081. Rational Sum 解析
- 爪哇(Java)的诞生、组成
- 机器学习 VS. 深度学习
- 数据挖掘之决策树介绍
- React Native原生模块向JS传递数据的几种方式(Android)
- Java中初始化和清理
- [linux上路] 开发环境准备四 Debian8 导入CA证书
- springmvc异常处理
- 用函数的递归强解数组极差问题