Leetcode学习（34）—— Move Zeroes

Given an array nums, write a function to move all 0’s to the end of it while maintaining the relative order of the non-zero elements.

For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3, 12, 0, 0].

Note:You must do this in-place without making a copy of the array.Minimize the total number of operations.

# -*- coding:utf-8 -*-class Solution(object):    def moveZeroes(self, nums):        return nums.sort(key=lambda x:1 if x==0 else 1)if __name__ == '__main__':    print(Solution().moveZeroes([0, 1, 0, 3, 12]))    # def moveZeroes(self, nums):    #     # lastZero 用于保存 list 最前方的 0 的下标    #     # 类比冒泡排序    #     lastZero = 0    #     for i in range(len(nums)):    #         if nums[i]:    #             nums[i], nums[lastZero] = nums[lastZero], nums[i]    #             lastZero += 1    #     return nums

nums.sort(key=lambda x:1 if x==0 else 1)

该语句表示，将 lambda 匿名函数应用于每一个 nums 的元素，之后将其进行排序