简单链表的实现

#include <iostream>using namespace std;struct Node{    int i;    Node *next=NULL;};int main() {   Node a;    a.i=1;    Node b;    b.i=2;    Node c;    c.i=3;    Node d;    d.i=9;    a.next=&b;    b.next=&d;    d.next=&c;    Node *iter=&a;    while (iter){        cout<<iter->i<<endl;       iter=iter->next;    }}