文章测试

来源:互联网 发布:c#windows窗体程序设计 编辑:程序博客网 时间:2024/06/06 03:23
SELECT p.prod_name, i.item_cnt    FROM (SELECT  prod_id, COUNT(*) item_cnt               FROM sales               GROUP BY prod_id) i RIGHT OUTER JOIN  products p    ON   i.prod_id  = p.prod_id;



SELECT p.prod_name, i.item_cnt    FROM (SELECT  prod_id, COUNT(*) item_cnt               FROM sales               GROUP BY prod_id) i RIGHT OUTER JOIN  products p    ON   i.prod_id  = p.prod_id;


0 0
原创粉丝点击