1010. 一元多项式求导 (25)

//#include<stdio.h>#include<stdlib.h>int main(){  int m,n,first=0;  while(scanf("%d%d",&m,&n)!=EOF)  {    if(n*m)    {      if(first)        printf(" ");      else        first = 1;      printf("%d %d",m*n, n-1);    }  }  if(!first)    printf("0 0");  return 0;}