HDU 5980

 Find Small A
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 1170 Accepted Submission(s): 578


Problem Description
As is known to all,the ASCII of character 'a' is 97. Now,find out how many character 'a' in a group of given numbers. Please note that the numbers here are given by 32 bits’ integers in the computer.That means,1digit represents 4 characters(one character is represented by 8 bits’ binary digits).


Input
The input contains a set of test data.The first number is one positive integer N (1≤N≤100),and then N positive integersai (1≤ ai≤2^32 - 1) follow


Output
Output one line,including an integer representing the number of 'a' in the group of given numbers.


Sample Input

3
97 24929 100



Sample Output

3

题意：就是输入N个整数，那么这N个整数不都是以32位存的吗？现在让你把输入的每一个数如果写成32位，把它分为4份，每次取其中的8位为一个数，为这个数是不是97；要求你记录这N个数进过这样的操作后其中有几个97？

#include <iostream>#include <string.h>#include <stdio.h>#include <math.h>#include <algorithm>#define N 100000using namespace std;int main(){    int n;    while(~scanf("%d",&n))    {long long cnt=0;long long p = 2*2*2*2*2*2*2*2- 1;for(int i=0;i<n;i++)        {long long d;scanf("%lld",&d);long long temp=d;int j=0;while(j<=4)               {    int k=8*j;j++;temp=d >> k;temp=temp&p;if(temp==97)cnt++;}}printf("%lld\n",cnt);    }    return 0;}