url解码

来源：互联网发布：大学生网络创业问题编辑：程序博客网时间：2024/05/19 12:38
#include <stdio.h>#include <stdlib.h>#include <string.h>char ascii_to_char(char src);char* url_decode(const char* src,char* dst,int len);int main(int argc,char* argv[]){    char* src = "%E6%98%A5%E8%8A%82";    int len = strlen(src);    char *dst = (char*)malloc(len+1);    url_decode(src,dst,len);    puts(dst);    if(!dst)    {        free(dst);    }    return 0;}//将字符形式的ascii码转换成对应的整型的ascii吗char ascii_to_char(char src){        if(src >= 'A' && src <= 'F')    {        src-=55;    }    else if( src >= '0' && src <= '9')    {        src-=48;    }    else    {        return -1;    }    return src;}char* url_decode(const char* src,char* dst,int len){            //char* temp = (char*)malloc(len+1);                //strncpy(temp,src,len+1);    int i=0;    int j=0;    for(;i<len;)    {        if( src[i] == '%' )        {            i++;            dst[j]= ( ((  ascii_to_char(src[i])) << 4) | ( ascii_to_char(src[i+1]) ) );            j++;            i+=2;        }        else        {            dst[j]=src[i];            i++;            j++;        }    }    dst[j]='\0';    return dst;}
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