脚本的最大优势，就是简化工作步骤提高工作效率，你看出来了吗？有没有看到这段代码的作用呢？

来源：互联网发布：学java入门什么书推建编辑：程序博客网时间：2024/05/17 18:41

下面这段代码，是为了提高刷机的生产效率！掌握基本的shell编程，很多事情都会变得如此的简单。

update.sh

#! /bin/sh set -xecho "start update ..."    if [ -f /mnt/sd_card/aoni_update/app_5.1.6.jffs2 ] && [ -f /mnt/sd_card/aoni_update/close_watchdog ] && [ -f /mnt/sd_card/aoni_update/gm_led ];thenecho "file exist.continue!!"elseecho "file not exist.exit!!!"exit 0fiPROCESS_NUM_1=`ps | grep "main.V5.1.4.exe" | grep -v "grep" | wc -l`  PROCESS_NUM_2=`ps | grep "main.V5.1.5.exe" | grep -v "grep" | wc -l`  PROCESS_NUM_3=`ps | grep "main.V5.1.6.exe" | grep -v "grep" | wc -l`PROCESS_watchdog=`ps | grep "close_watchdog" | grep -v "grep" | wc -l`if [ $PROCESS_watchdog -eq 1 ];thenecho "Actually was runed upgrade.sh !!!!"exit 0fiNAME=main.V5.1.4.exeif [ $PROCESS_NUM_1 -eq 1 ]; then  NAME=main.V5.1.4.exe  fi  if [ $PROCESS_NUM_2 -eq 1 ]; then  NAME=main.V5.1.5.exe  fi  if [ $PROCESS_NUM_3 -eq 1 ]; then  NAME=main.V5.1.6.exe  fi  main_ID=`ps | grep "$NAME" | grep -v "grep" | awk '{print $1}'`  echo $main_IDkill -9 $main_ID  echo "kill main_ID done!!!"  echo "---------------"   daemon_ID=`ps | grep "daemon.exe" | grep -v "grep" | awk '{print $1}'`  echo $daemon_IDkill -9 $daemon_ID  echo "kill daemon_ID done!!!"  echo "---------------"    udhcpc_ID=`ps | grep "udhcpc" | grep -v "grep" | awk '{print $1}'`  echo $udhcpc_IDkill -9 $udhcpc_ID  echo "kill udhcpc_ID done!!!"  echo "---------------"   echo close watchdog ...cp /mnt/sd_card/aoni_update/close_watchdog /tmpcp /mnt/sd_card/aoni_update/gm_led /tmpcd /tmp./close_watchdog &if [ $? -eq 0 ];thenecho umount /mnt/mtdumount /mnt/mtdif [ $? -eq 0 ];thenecho "umount /mnt/mtd done!"flash_eraseall /dev/mtd4    if [ $? -eq 0 ];thenecho "flash_eraseall done!"        flashcp /mnt/sd_card/aoni_update/app_5.1.6.jffs2 /dev/mtd4if [ $? -eq 0 ];thenecho "flashcp done!"echo "sync ..."syncecho "uptade success!!"if [ $? -eq 0 ];then./gm_led &fififififi

另外补充一个问题就是关于看门狗的，umount分区之前，必须先kill掉存在该分区的进程，但是由于启用了看门狗，如果直接kill线程，看门狗就会一直重启系统而无法正常工作，首先第一想法是直接强制关闭，尝试了命令和程序貌似不太好使，干脆！直接不停的喂狗！代码如下：

close_watchdog.c

#include <fcntl.h>#include <errno.h>#include <sys/ioctl.h>#include <linux/watchdog.h>#define TIMEOUT 10#define WDT_DEVICE_FILE "/dev/watchdog"int main(void){    int g_watchdog_fd = -1;    int timeout = 0;    char arg = 1;    g_watchdog_fd = open(WDT_DEVICE_FILE, O_RDWR);    if (!g_watchdog_fd)    {        printf("Error in file open WDT device file(%s)...\n", WDT_DEVICE_FILE);        return 0;    }    ioctl(g_watchdog_fd, WDIOC_SETOPTIONS, WDIOS_ENABLECARD);#if 1    ioctl(g_watchdog_fd, WDIOC_GETTIMEOUT, &timeout);    printf("default timeout %d sec.\n", timeout);    printf("We reset timeout as %d sec.\n", TIMEOUT);    timeout = TIMEOUT;    ioctl(g_watchdog_fd, WDIOC_SETTIMEOUT, &timeout);    ioctl(g_watchdog_fd, WDIOC_GETTIMEOUT, &timeout);    if (timeout != TIMEOUT)    {        printf("WDT timeout reset error.\n");        return 1;    }    while (1)    {        write(g_watchdog_fd, &arg, sizeof(arg));        ioctl(g_watchdog_fd, WDIOC_KEEPALIVE, 0);        sleep(2);    }#endif    ioctl(g_watchdog_fd, WDIOC_SETOPTIONS, WDIOS_DISABLECARD);    close(g_watchdog_fd);    printf("watchdog_disable_dog!!!\n");    return 0;}

阅读全文

0 0