POJ3461 Oulipo(字符串匹配KMP)
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题目:
Description
The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book:
Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…
Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive 'T's is not unusual. And they never use spaces.
So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A', 'B', 'C', …, 'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap.
Input
The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:
- One line with the word W, a string over {'A', 'B', 'C', …, 'Z'}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W).
- One line with the text T, a string over {'A', 'B', 'C', …, 'Z'}, with |W| ≤ |T| ≤ 1,000,000.
Output
For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T.
Sample Input
3BAPCBAPCAZAAZAZAZAVERDIAVERDXIVYERDIAN
Sample Output
130
Source
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思路:KMP模板题,求的是子串在原串中出现的次数
代码:
#include<cstdio>#include<cstring>#include<string>#include<set>#include<iostream>#include<stack>#include<queue>#include<vector>#include<algorithm>#define mem(a,b) memset(a,b,sizeof(a))#define inf 0x3f3f3f3f#define mod 10000007#define debug() puts("what the fuck!!!")#define N 1000010#define ll longlongusing namespace std;char s1[N],s2[N];int next[N];int len1,len2,n,m;void get_next(){ int j=0,k=-1; next[0]=-1; while(j<len1) { if(k==-1||s1[j]==s1[k]) next[++j]=++k; else k=next[k]; }}int KMP_count(){ int ans=0; int i,j=0; if(len1==1&&len2==1) { if(s1[0]==s2[0]) return 1; else return 0; } get_next(); for(int i=0; i<len2; i++) { while(j>0&&s2[i]!=s1[j]) j=next[j]; if(s1[j]==s2[i]) j++; if(j==len1) { ans++; j=next[j]; } } return ans;}int main(){ int t; scanf("%d",&t); while(t--) { scanf("%s%s",s1,s2); len1=strlen(s1); len2=strlen(s2); printf("%d\n",KMP_count()); } return 0;}
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