python 删除指定时间间隔之前的文件

遍历指定文件夹下的文件，根据文件后缀名，获取指定类型的文件列表；根据文件列表里的文件路径，逐个获取文件属性里的“修改时间”，如果“修改时间”与“系统当前时间”差值大于某个值，则删除该文件。

#!/usr/bin/env python# -*- coding: utf-8 -*-"""Document: Remove Synctoycmd sync expired .tmp files"""import osimport timeimport datetimedef diff():    '''time diff'''    starttime = datetime.datetime.now()    time.sleep(10)    endtime = datetime.datetime.now()    print "time diff: %d" % ((endtime-starttime).seconds)def fileremove(filename, timedifference):    '''remove file'''    date = datetime.datetime.fromtimestamp(os.path.getmtime(filename))    print date    now = datetime.datetime.now()    print now    print 'seconds difference: %d' % ((now - date).seconds)    if (now - date).seconds > timedifference:        if os.path.exists(filename):            os.remove(filename)            print 'remove file: %s' % filename        else:            print 'no such file: %s' % filenameFILE_DIR = 'D:/'if __name__ == '__main__':    print 'Script is running...'    #diff()    while True:        ITEMS = os.listdir(FILE_DIR)        NEWLIST = []        for names in ITEMS:            if names.endswith(".txt"):                NEWLIST.append(FILE_DIR + names)        #print NEWLIST        for names in NEWLIST:            print 'current file: %s' % (names)            fileremove(names, 10)        time.sleep(10)    print "never arrive..."