USACO Section 1.2 Palindromic Squares
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这题就是简单的把从1到300的数用给定B进制表示一下,再把他的平方也表示一下,如果平方的B进制表示是回文数的话,就输出这个数还有他的平方的B进制表示。
代码如下:
/*ID: 13913351LANG: CTASK:palsquare*/#include<stdio.h>#include<string.h>char num[21]={"0123456789ABCDEFGHIJ"};void shift(int m,int n,char res[32]){ int k=0; while(n!=0) { res[k++]=num[n%m]; n/=m; } res[k]='\0';} int main(){ FILE *fin = fopen ("palsquare.in", "r"); FILE *fout = fopen ("palsquare.out", "w"); int m; fscanf(fin,"%d",&m); char x[32],res[32]; int i,j; for(i=1;i<=300;i++) { // printf("%d\n",i); shift(m,i,x); shift(m,i*i,res); for(j=0;j<strlen(x)/2;j++) { char ch; ch=x[j]; x[j]=x[strlen(x)-1-j]; x[strlen(x)-1-j]=ch; } for(j=0;j<strlen(res)/2;j++) { if(res[j]!=res[strlen(res)-j-1]) { break; } } if(j>=strlen(res)/2) { fprintf(fout,"%s %s\n",x,res); } } return 0;}
祝大家学习愉快哦!!
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