An Easy Task

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4555 Accepted Submission(s): 2558 

Problem Description

Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?

Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.

Note: if year Y is a leap year, then the 1st leap year is year Y.

 

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains two positive integers Y and N(1<=N<=10000).

 

Output

For each test case, you should output the Nth leap year from year Y.

 

Sample Input

32005 251855 122004 10000

 

Sample Output

2108190443236
Hint
We call year Y a leap year only if (Y%4==0 && Y%100!=0) or Y%400==0.
 

 

Author

Ignatius.L

一个个数下去就行了

#include <iostream>using namespace std;int main(){    int n,i,m;    int t;    cin>>t;    while(t--)    {        cin>>n>>m;        int j=0;        for(i=n;;i++)        {            if(i%4==0&&i%100!=0||i%400==0)            {                j++;            }            if(j==m)break;        }        cout<<i<<endl;    }    return 0;}