python使用socket实现多线程端口扫描

使用socket主要是判断是否端口能否联通
socket<<详情参考>>

1.socket.connect() 检测端口，若端口不能联通，则会抛出异常，若无异常，则端口存活，使用try-except异常捕获处理，进而进行端口扫描

这里将使用100个线程，每个端口连接都要检查是否超过65535

#coding=utf8import socketimport threadingdef scan(host,cport):    for x in range(660):       p=x+660*cport       try:         if p < 65535:             s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)             s.connect((host, p))             s.settimeout(0.1)             print "local open port : %d"%p             s.close()         else :             break       except Exception:           passlist = []for i in range(100):        t = threading.Thread(target=scan,args=('localhost',i,))        list.append(t)        t.start()for threadinglist in list:        threadinglist.join()

输出：

local open port : 22local open port : 111local open port : 34172local open port : 49716local open port : 51078

2.socket.connect_ex() 若联通则返回为0，否则返回为非0
依据connect_ex返回值判断端口是否存活

import socket import threading from Queue import Queue def scan(port):   s = socket.socket()   s.settimeout(1)   if s.connect_ex(('localhost', port)) == 0:      print "local open port : %d"%port  s.close() def worker():   while not q.empty():     port = q.get()     try:       scan(port)     finally:       q.task_done() if __name__ == '__main__':   q = Queue()   map(q.put,xrange(1,65535))   threads = [threading.Thread(target=worker) for i in xrange(100)]   map(lambda x:x.start(),threads)   q.join() 

输出：

local open port : 22local open port : 25local open port : 111local open port : 631local open port : 35156local open port : 38929local open port : 51078