list<Object[]>按object里面数值大小排序

List<Object[]> projectCount = new ArrayList<Object[]>();for(int i=0;i<years.length;i++){projectCount.addAll(productManageJdbcDAO.topFiveProject(years[i]));}Collections.sort(projectCount, new Comparator<Object[]>() {@Overridepublic int compare(Object[] o1, Object[] o2) {double d1 = (Double) o1[3];double d2 = (Double) o2[3];return (int) (d2 - d1);}});